1tan 2 x=22tanx tan 2 x2tanx1=0 (tanx1) 2 =0 tanx=1 1 Thank You ANSWER Related Questions Observation solutions of maths activity Report ; 2tanx1 分之一的积分 tanx分之一的不定积分 —— ∫tan^2 x dx = ∫sinx dsecx = sinx secx ∫secx dsinx = sinx secx ∫secx cosx dx = sinx secx ∫ dx = sinx secx x ∫1/√x dx = ∫ x^(1/2) dx = 2 x^(1/2) 所以原式 = sinx secx x 2√x Precalculus Prove the following identities 1 1cosx/1cosx = secx 1/secx 1 2 (tanx cotx)^2=sec^2x csc^2x 3 cos (xy) cos (xy)= cos^2x sin^2y
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